Home TeXt - MathJax When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \[x_1 = {-b + \sqrt{b^2-4ac} \over 2a}\] \[x_2 = {-b - \sqrt{b^2-4ac} \over 2a} \notag\]Read more TeXt Nov 08, 2022
TeXt - MathJax When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \[x_1 = {-b + \sqrt{b^2-4ac} \over 2a}\] \[x_2 = {-b - \sqrt{b^2-4ac} \over 2a} \notag\]Read more TeXt Nov 08, 2022